[e^(i*pi)] + 1 = me (kvschwartz) wrote in braintango,
[e^(i*pi)] + 1 = me
kvschwartz
braintango

Deep Thoughts... by Kevin Schwartz (dt11)

My first girlfriend told me I was an amazing kisser, but I am not sure I really believe her. After all, what else are you gonna tell your kid brother? "Dad was better?"
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